![PPT - 1 mole = 6.02 X 10 23 things This is called Avogadro's number PowerPoint Presentation - ID:4272623 PPT - 1 mole = 6.02 X 10 23 things This is called Avogadro's number PowerPoint Presentation - ID:4272623](https://image2.slideserve.com/4272623/slide1-l.jpg)
PPT - 1 mole = 6.02 X 10 23 things This is called Avogadro's number PowerPoint Presentation - ID:4272623
Lithium has a BCC structure. Its density is 530 kg m^-3 and its atomic mass is 6.94 g mol^-1 . Calculate the edge length of a unit cell of Lithium metal: ( NA = 6.02 × 10^23 mol^-1 )
12 g C - 12 contains 6.022 × 10^23 atoms of carbon.(a) 6.022 × 10^23 is known as .............(b) Calculate the number of carbon atoms present in 48 g C - 12.(c)
![SOLVED: Calculate the number of Br atoms in 20.0g of liquid bromine (Br2). NOTE: Avogadro's number is 6.02 x 1023 A 7.53*10^23 B. 1.51*10^23 C. 3.01*10 ^23 D. 3.77*10^23 E. Nor correct response SOLVED: Calculate the number of Br atoms in 20.0g of liquid bromine (Br2). NOTE: Avogadro's number is 6.02 x 1023 A 7.53*10^23 B. 1.51*10^23 C. 3.01*10 ^23 D. 3.77*10^23 E. Nor correct response](https://cdn.numerade.com/ask_previews/d5e89a5a-dba4-4e90-8c36-251b7c9c4b6f_large.jpg)
SOLVED: Calculate the number of Br atoms in 20.0g of liquid bromine (Br2). NOTE: Avogadro's number is 6.02 x 1023 A 7.53*10^23 B. 1.51*10^23 C. 3.01*10 ^23 D. 3.77*10^23 E. Nor correct response
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